t^2=36/121

Solution for t^2=36/121 equation:

t^2=36/121

We move all terms to the left:

t^2-(36/121)=0

We add all the numbers together, and all the variables

t^2-(+36/121)=0

We get rid of parentheses

t^2-36/121=0

We multiply all the terms by the denominator


t^2*121-36=0

Wy multiply elements

121t^2-36=0

a = 121; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·121·(-36)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*121}=\frac{-132}{242}
=-6/11
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*121}=\frac{132}{242}
=6/11
$